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480=3n^2-90n-720
We move all terms to the left:
480-(3n^2-90n-720)=0
We get rid of parentheses
-3n^2+90n+720+480=0
We add all the numbers together, and all the variables
-3n^2+90n+1200=0
a = -3; b = 90; c = +1200;
Δ = b2-4ac
Δ = 902-4·(-3)·1200
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-150}{2*-3}=\frac{-240}{-6} =+40 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+150}{2*-3}=\frac{60}{-6} =-10 $
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